Excellent, thanks for the useful info On Jan 15, 3:00 pm, Daniel Roseman <[email protected]> wrote: > On Jan 15, 1:47 pm, grimmus <[email protected]> wrote: > > > > > Hi, > > > I have a view that gets the latest videos: > > > videos = Video.objects.filter(category=category,active=1).order_by > > ('-hit_count') > > > In my template i would like the first result to appear in the primary > > block and the other results to appear in the secondary block > > > {% block primary %} > > SHOW FIRST VIDEO HERE > > {% endblock %} > > > {% block secondary %} > > <ul> > > {% for video in videos %} > > <li> > > SHOW OTHER VIDEOS HERE > > </li> > > {% endfor %} > > </ul> > > {% endblock %} > > > How could i show the first result in 'block primary' without using a > > for loop and how could i begin the loop in 'block secondary' at the > > second place (i.e. not showing the first video here) ? > > > Thanks for any tips, i hope i have been clear. > > {{ videos.0 }} > > {{ videos|slice:"1:" }} > > Note this will make two separate queries to the database. You might > want to call list() on the queryset in the view to force it to > evaluate it before slicing. > -- > DR. > -- > DR.
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