On Feb 8, 2010, at 7:56 AM, eaman wrote:
I'm up to code those two methods...
If some one is interested in this thread I managed to code
these two methods: get_next | get_prev
in order to get a previous or next item in a set right from my model:
- http://dpaste.com/155961/
Now that you've got a date attribute, why not use that for next and
previous?
If you don't want to do that, you still might consider returning a
real object instance, and then giving the model a get_absolute_url()
method and calling that in the template. That will save you hardcoding
the links in the template.
But if it's just an id you want, the following might be more efficient:
def get_next(self):
all_ids = Foto.objects.filter(galleria = self.galleria,
id__gt=self.id).values_list("id",flat=True).order_by("id")
try:
return min(all_ids)
except ValueError:
return None
Then reverse that (id__lt=self.id and use the max python function) for
get_prev()
Hope that's helpful,
Eric
- Is there a better way to get the highest 'previous' item then
using
aggregate(Max('id')) ?
- I guess the if /else conditional loop that should check the
existence of the prev | next item is suboptimal...
/eaman
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