Thanks Ralf. Your solution will work for this particular case and
similar ones, but not for "forsight.com".
The problem is that I am collecting both domain names and host names
from different internet sources and I need a way to obtain the second
level domain name regardless of the type.
Any other solutions?
Cheers,
Marc
Al 25/07/10 13:00, En/na Ralf Weber ha escrit:
> Moin!
>
> On 24.07.2010, at 17:25, Marc Vilanova wrote:
>> I am trying to get the second level domain name from a host name using
>> the "dns.resolver.zone_for_name" function as it is shown in the
>> following piece of code, but I am having problems with some TLDs and ccTLDs.
>>
>> host_name = "www.forsight.com.au"
>> domain_name = dns.resolver.zone_for_name(host_name,resolver=my_resolver)
>> print str(domain_name)
>> com.au. (correct, but I was interested in obtaining "forsight.com.au.")
> Well this function will only work if the domain is actually delegated, which
> forsight.com.au is not:
> rwe...@pinkfloyd:~/source/dnspython-1.8.0/dns$ dig SOA forsight.com.au
>
> ; <<>> DiG 9.6.0-APPLE-P2 <<>> SOA forsight.com.au
> ;; global options: +cmd
> ;; Got answer:
> ;; ->>HEADER<<- opcode: QUERY, status: NXDOMAIN, id: 12026
> ;; flags: qr rd ra; QUERY: 1, ANSWER: 0, AUTHORITY: 1, ADDITIONAL: 0
>
> ;; QUESTION SECTION:
> ;forsight.com.au. IN SOA
>
> ;; AUTHORITY SECTION:
> com.au. 0 IN SOA ns1.ausregistry.net.au.
> dns.ausregistry.net.au. 2040519490 14400 3600 3600000 14400
>
>> Is there a better way to do it that will work for all TLDs and ccTLDs?
>> Thanks in advance.
> If you are just interested in skipping the first label a:
> domain = str (dns.name.from_text("www.forsight.com.au").parent())
> might help.
>
> So long
> -Ralf
> ---
> Ralf Weber (Internet Citizen)
> e: [email protected]
>
>
>
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