In the chunk-element-content template there isn't enough information to
distinguish between the context of the index.html chunk and the lots chunk.
So I think you would have to customize two templates.
1. Customize the template named process-chunk in html/chunk-common.xsl to
change the call to chunk-element-content to include an additional parameter
named filename, which is set to $filename (that variable is set just before
the call to write.chunk).
2. Then customize the chunk-element-content template to accept the new
parameter and add an xsl:choose statement to act on its value.
Bob Stayton
Sagehill Enterprises
[EMAIL PROTECTED]
----- Original Message -----
From: "Boris" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Thursday, December 04, 2008 5:44 AM
Subject: [docbook-apps] Re: Customize user.footer.content for one webpage
only?
On Wed, 03 Dec 2008 23:57:00 +0100, Boris <[EMAIL PROTECTED]> wrote:
I've defined the template user.footer.content to append a copyright note
to every webpage (I use chunking). For the first page (index.html) I'd
like to customize user.footer.content: The version number and the
publishing date should be appended, too.
Now I've seen that the template chunk-element-content in
chunk.common.xsl simpy always calls the template user.footer.content -
no matter what webpage is written. That's why I guess I need to find out
in user.footer.content somehow to which file the content is currently
appended: If it's the beginning of the book (the book's titlepage)
something more should be appended. Is this possible? I think I need a
<xsl:if test="..."> but what exactly do I have to test?
I think I should have been more specific: I can test if the current node
is book. However as I've set chunk.tocs.and.lots to 1 to put the toc into
its own file the footer content is appended to that page, too (as there
the current node is also book). I think I need to check the current
filename. But how do I find out?
Boris
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