Re: [docbook-apps] breadcrumbs root node

[Bob Stayton]

You could change your select statement to require a parent on each element:



            <xsl:for-each select="$this.node/ancestor::*[parent::*]">


Since the root node does not have a parent, it would not be selected.  I have 
not tested it, but I think it would work.

Bob Stayton
Sagehill Enterprises
b...@sagehill.net


  ----- Original Message ----- 
  From: Laurie Burley 
  To: docbook-apps@lists.oasis-open.org 
  Sent: Monday, August 03, 2009 1:21 AM
  Subject: [docbook-apps] breadcrumbs root node


  Hi,

   

  Has anyone figured out a way to remove the root node from breadcrumbs in 
their html output?

   

  I am using the following code to generate my breadcrumbs:

   

  <xsl:template name="breadcrumbs">

        <xsl:param name="this.node" select="."/>

        <table class="headertable">

           <tr>

              <td width="95%">

              <div class="breadcrumbs">

              <xsl:for-each select="$this.node/ancestor::*">

                <span class="breadcrumb-link">

                   <a>

                  <xsl:attribute name="href">

                     <xsl:call-template name="href.target">

                     <xsl:with-param name="object" select="."/>

                     <xsl:with-param name="context" select="$this.node"/>

                     </xsl:call-template>

                  </xsl:attribute>

                  <xsl:apply-templates select="." mode="title.markup"/>

                  </a>

               </span>

               <xsl:text> &gt; </xsl:text>

           </xsl:for-each>

   

  <!-- And display the current node, but not as a link -->

  <span class="breadcrumb-node">

     <xsl:apply-templates select="$this.node" mode="title.markup"/>

  </span>

  </div></td>

  <!--add a logo to the top right corner-->

  <xsl:call-template name="logo"/>

  </tr>

  </table>

  </xsl:template>

   

  Any help would be greatly appreciated,

   

  Kind Regards,

   

  Laurie Burley