Re: [docbook-apps] How to transform the content of a element ?

[Maxime Bégnis]

Hello, In the <xsl:variable name="texte" select="translate(text(),'T','Z')" /> statement, the 'text()' function only selects the direct child text node(s)(I think only the first actually) of the para element. Try this: <xsl:variable name="texte">     <xsl:for-each select=".//text()">         <xsl:value-of select="translate(.,'T','Z')" />     </xsl:for-each> </xsl:variable> I hope this helps. Maxime Bégnis Développeur max...@neodoc.biz Tél: 09.54.96.99.55 - Fax: 09.59.96.99.55 http://www.neodoc.fr/ 5, rue de la Touloubre 13770 Venelles Le 25/05/2011 13:24, Christophe HARO a écrit : Hi all, With an element <para> like this : <para> This is a test. <emphasis> This is another phrase. </emphasis> </para> I want to obtain : Zhis is a test. Zhis is another phrase. where 'Z' replaces all occurrences of 'T'. The customization layer is : <!-- Essai de substitution --> <xsl:template match="db5:para"> <xsl:variable name="texte" select="translate(text(),'T','Z')" /> <fo:block xsl:use-attribute-sets="normal.para.spacing"> <xsl:value-of select="$texte" /> <xsl:call-template name="anchor" /> <xsl:apply-templates /> </fo:block> </xsl:template> The content of <para> is outputed like this : Zhis is a test. This is a test. This is another phrase. 1) I do not understand why the content before <emphasis> is outputed two times ; 2) how can I customize so that the content of <emphasis> will be also translated. For the first point, I think that $texte is outputed (Zhis is a test.) and then <apply-templates> output This is a test. Is that right ? Can someone help me ? Many thanks.