Ok, I think I have it.
As I am using several transformations, the processing-instruction is no more
available at the step where I need it.
So, I have added a <linebreak/> node in my XML, that I treat in my
customization template
<xsl:template match="d:linebreak">
<br/>
</xsl:template>
Or <fo:block/> in the xsl-fo layer.
Now, it is working
Regards,
Fabien (One can't be wrong while doing both questions and answers :) )
-----Message d'origine-----
De : Fabien Tillier [mailto:[email protected]]
Envoyé : lundi 23 janvier 2012 14:39
À : [email protected]
Objet : [docbook] RE: Line break mistery
Seems it doesn't work in HTML neither...
I have to dig a bit more. Sorry for the noise..
Regards,
Fabien
-----Message d'origine-----
De : Fabien Tillier [mailto:[email protected]]
Envoyé : lundi 23 janvier 2012 14:26
À : [email protected]
Objet : [docbook] Line break mistery
Hi List.
I am using the XSL Stylesheets (v 1.75.1) to transform some docbook xml to
either HTML or XSL-FO.
I would like to have some line-breaks, thus I added
<?linebreak?>
Instructions in my XML.
It is working in my HTML template with
<xsl:template match="processing-instruction('linebreak')">
<br/>
</xsl:template>
(I have a customization template)
But when I switch to xsl-fo output,
My template (here with big text so that I can see it easily in the output) is
never called.
<xsl:template match="processing-instruction('linebreak')">
###########################################################
<fo:block></fo:block>
###########################################################
</xsl:template>
Is there a parameter or something to be set so that this processing instruction
can be used ?
Thanks in advance,
Best regards,
Fabien
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