Without it, the constructor may be automatically transformed to an
operator= for the same type. Take for example this code:
class A
{
public:
A(int N) { x = new real[N]; }
~A() { delete [] x; }
};
A a(100);
a = 200; // legal without explicit above
which will lead to disaster.
--
Martin
2008/4/29 <[EMAIL PROTECTED]>:
> > All constructors with a single argument.
> >
> > --
> > Martin
> >
> >
>
> Why ? What does it mean ?
>
> Kent
>
>
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