Try the XPath syntax "/*/*[local-name()!='ContactInfo']" .
That should give you what you want. I verified it with XPE, but have not tried it on DOM4J.

Let me know if it works. :-)
Later,
Dave


Pae Choi wrote:
Thank you for your reply as well as code snippet. But that's not exactlly
what I was looking for.
My applogies if I did not explained well in my prevous message. The
code snippet in your message will be able to get the <ContactInfo>
subemelement fine. And I have no problem to getting that.
My question was to get the rest of XML DOM, excluding the prviously
selected sublelement, <ContactInfo>. To wit, I am looking for a simple
way to get the result without parsing the XML document by excluding
the previously selected subelement. The result I am expecting to get
is as follows:
Initial XML:
/<Patient>/
/ <Age>39</Age>///
/ <Gender>Female</Gender>///
/ <ContactInfo>///
/ <PhoneNumber>123-456-7890</PhoneNumber>///
/ <EmailAddress>[EMAIL PROTECTED]</EmailAddress>///
/ </ContactInfo>///
/</Patient>///
The result XML:
/<Patient>/
/ <Age>39</Age>///
/ <Gender>Female</Gender>///
/</Patient>///
Thank you.
Any more comments?
Regards,
Pae

----- Original Message -----
*From:* Benjamin Kopic <mailto:[EMAIL PROTECTED]>
*To:* Pae Choi <mailto:[EMAIL PROTECTED]>
*Cc:* [EMAIL PROTECTED]
<mailto:[EMAIL PROTECTED]>
*Sent:* Sunday, November 17, 2002 4:07 AM
*Subject:* Re: [dom4j-user] XPath result from a DOM and the Rest of DOM

If I understand you correctly, the following will return <Patient>
element:


SAXReader reader = new SAXReader();
Document document = reader.read( new File( "patient_records.xml" ) );
Element contactInfo = document.selectSingleNode( "//ContactInfo",
"." );
Element patient = contactInfor.getParent();


Then you can use the Node API to traverse the <Patient> element
returned.

Also, if <Patient> is the root element, then you can do the following:

SAXReader reader = new SAXReader();
Document document = reader.read( new File( "patient_records.xml" ) );
Element patient = document.getRootElement();



Best regards

Ben


On Sat, 2002-11-16 at 23:52, Pae Choi wrote:

/Say we have an XML document as follows:///
////
/<Patient>///
/ <Age>39</Age>///
/ <Gender>Female</Gender>///
/ <ContactInfo>///
/ <PhoneNumber>123-456-7890</PhoneNumber>///
/ <EmailAddress>[EMAIL PROTECTED]</EmailAddress>///
/ </ContactInfo>///
/</Patient>///
////
/And we use the XPath to only get the <ContactInfo>, e.g.,///
/"//ContactInfo" which should get the result as follows;///
////
/ <ContactInfo>///
/ <PhoneNumber>123-456-7890</PhoneNumber>///
/ <EmailAddress>[EMAIL PROTECTED]</EmailAddress>///
/ </ContactInfo>///
////
/My question is:///
////
/[Q] Is there way to get the rest of XML document in a simple///
/ way. The rest of XML document should be as follows;///
////
/<Patient>///
/ <Age>39</Age>///
/ <Gender>Female</Gender>///
/</Patient>///
////
/Any comments? Thank you.///
////
/Regards,///
////
////
/Pae///
////
////
////

--
benjamin kopic
m: +44 (0)780 154 7643
t: +44 (0)20 7794 3090
e: [EMAIL PROTECTED]
w: http://www.panContext.com/


--

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