[dom4j-user] comparing nodes (was: RE: bug in serialization)

Maarten Coene Tue, 22 Jun 2004 05:05:03 -0700

The reason is that dom4j nodes use identity based equality: 2 nodes are equal if they reference the same object instance. In your case: the documents are different objects, so the nodes will be different objects too and the equals() method will always return false.

To solve your problem: you could iterate the 2 lists manually and use org.dom4j.util.NodeComparator to compare the nodes:

if (listNodesOriginal.size() != listNodesNew.size()) {
   return false;
} else {
   NodeComparator comparator = new NodeComparator();
   for (int i = 0; i < listNodesOriginal.size(); i++) {
       Node orig = (Node) listNodesOriginal.get(i);
       Node newNode = (Node) listNodesNew.get(i);
       if (comparator.compare(orig, newNode) != 0) {
            return false;
       }
   }
   return true;
}

regards,
Maarten

Z Z wrote:

Hello ,
I need to compare two XPath results Lists on different document.
this is how i do that now, why doen't it work ?
( i want to compare the lists returns by XPath by value and not by
references to the nodes - deeo compare)
here is my code :
   List listNodesOriginal = m_leftDocument.selectNodes(m_strXPathLeft);
   List listNodesNew = newLeftDocument.selectNodes(m_strXPathLeft);
   if ( listNodesOriginal.equals(listNodesNew))
       return false;
   else
       return true;
m_leftDocument and newLeftDocument have been read from different xml files. ( no common references to same nodes) my code, always returns false, althought for some XPath expressions i need it to return true,
please help.
thank you.
Grosman
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[dom4j-user] comparing nodes (was: RE: bug in serialization)

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