Re: [dom4j-user] XPath result from a DOM and the Rest of DOM

James Strachan Mon, 18 Nov 2002 21:57:54 -0800

Just remove the ContactInfo element from the document and what you have left will be what you need..

Document patient = ...;

Node contactInfo = patient.selectSingleNode("/Patient/ContactInfo");

// remove it

contactInfo.detach();

// now the patient document looks like the expected result

James
-------
http://radio.weblogs.com/0112098/

----- Original Message -----

From: Pae Choi

To: Benjamin Kopic

Cc: [EMAIL PROTECTED]

Sent: Sunday, November 17, 2002 4:12 PM

Subject: Re: [dom4j-user] XPath result from a DOM and the Rest of DOM

Thank you for your reply as well as code snippet. But that's not exactlly

what I was looking for.

My applogies if I did not explained well in my prevous message. The

code snippet in your message will be able to get the <ContactInfo>

subemelement fine. And I have no problem to getting that.

My question was to get the rest of XML DOM, excluding the prviously

selected sublelement, <ContactInfo>. To wit, I am looking for a simple

way to get the result without parsing the XML document by excluding

the previously selected subelement. The result I am expecting to get

is as follows:

Initial XML:

<Patient>
    <Age>39</Age>
    <Gender>Female</Gender>
    <ContactInfo>
        <PhoneNumber>123-456-7890</PhoneNumber>
        <EmailAddress>[EMAIL PROTECTED]</EmailAddress>
    </ContactInfo>
</Patient>

The result XML:

<Patient>
    <Age>39</Age>
    <Gender>Female</Gender>
</Patient>

Thank you.

Any more comments?

Regards,

Pae
----- Original Message -----

From: Benjamin Kopic

To: Pae Choi

Cc: [EMAIL PROTECTED]

Sent: Sunday, November 17, 2002 4:07 AM

Subject: Re: [dom4j-user] XPath result from a DOM and the Rest of DOM

If I understand you correctly, the following will return <Patient> element:

SAXReader reader = new SAXReader();
Document document = reader.read( new File( "patient_records.xml" ) );
Element contactInfo = document.selectSingleNode( "//ContactInfo", "." );
Element patient = contactInfor.getParent();

Then you can use the Node API to traverse the <Patient> element returned.

Also, if <Patient> is the root element, then you can do the following:

SAXReader reader = new SAXReader();
Document document = reader.read( new File( "patient_records.xml" ) );
Element patient = document.getRootElement();

Best regards

Ben

On Sat, 2002-11-16 at 23:52, Pae Choi wrote:
Say we have an XML document as follows:

<Patient>
    <Age>39</Age>
    <Gender>Female</Gender>
    <ContactInfo>
        <PhoneNumber>123-456-7890</PhoneNumber>
        <EmailAddress>[EMAIL PROTECTED]</EmailAddress>
    </ContactInfo>
</Patient>

And we use the XPath to only get the <ContactInfo>, e.g.,
"//ContactInfo" which should get the result as follows;

    <ContactInfo>
        <PhoneNumber>123-456-7890</PhoneNumber>
        <EmailAddress>[EMAIL PROTECTED]</EmailAddress>
    </ContactInfo>

My question is:

[Q] Is there way to get the rest of XML document in a simple
      way. The rest of XML document should be as follows;

<Patient>
    <Age>39</Age>
    <Gender>Female</Gender>
</Patient>

Any comments? Thank you.

Regards,

Pae
-- 
benjamin kopic
m: +44 (0)780 154 7643
t: +44 (0)20 7794 3090
e: [EMAIL PROTECTED]
w: http://www.panContext.com/

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