Nope. XPath spec says that a namestep w/o a prefix is in the
null namespace, not the default namespace.
So, you have to bind a prefix.
-bob
On Tue, 22 Jun 2004 [EMAIL PROTECTED] wrote:
> On Tuesday 22 June 2004 17:10, you wrote:
> > Document doc = ...;
> > XPath xpath = doc.createXPath("/html:html/html:head/html:title");
> > // manually tell the xpath about our prefix
> > xpath.setNamespaceContext(Collections.singletonMap("html",
> > "http://www.w3.org/1999/xhtml";);
>
> There's no XPath.setNamespaceContext(Map).
>
> > Element titleElem = (Element)xpath.selectSingleNode(doc);
>
> Can't I simply ignore the namespace somehow? I want to apply one XPath
> expression to all docs.
>
> As I workaround I could do a
>
> Node n =
> dom.selectSingleNode("/HTML/*[local-name()='HEAD']/*[local-name()='TITLE']");
>
> but this is ugly... :-(
>
>
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Bob McWhirter [EMAIL PROTECTED]
The Werken Company http://werken.com/
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