I am trying to cross a XML by means of the XPath, but this this giving the error me:
Invalid XPath expression: 'formulario/pasos'. Caused by: null The root of xml is form, and I have tried diverse variations and I do not understand that it happens. It wanted to know if somebody can help or a manual me in Spanish, position qeu my English is not very good. The Code is : public void buscaPorXpath1(Document doc)throws DocumentException{ List lista = doc.selectNodes("//formulario/pasos"); Node nodo = doc.selectSingleNode ("formulario/pasos/paso"); String nombre = nodo.valueOf( "@nombre" ); System.out.println("DEBUG_1"); } It does not enter the ClassX.buscaPorXpath1 call (doc), leaves to catch. Waiting for quick and an answer, thank you very much. chucky All the advantages of Linux Managed Hosting--Without the Cost and Risk! Fully trained technicians. The highest number of Red Hat certifications in the hosting industry. Fanatical Support. Click to learn more http://sel.as-us.falkag.net/sel?cmd=lnk&kid=107521&bid=248729&dat=121642 _______________________________________________ dom4j-user mailing list dom4j-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/dom4j-user