Certainly, if MTTF = 10000 hrs =~ 400+ days, then half the units can be
expected to fail at less than that period - and some proportion of that 50%
within a one-year warranty (if such exists). I don't have the formulae to
hand to calculate the exact numbers.

I suspect the hapless coder producing the web doc was given some
hallucinated specs to work form and '10000' looks good.


best regards,
웃
Victor Churchill,
Netley Abbey, Southampton



On Wed, 10 Jun 2026 at 19:34, Peter Merchant <[email protected]>
wrote:

> 4 days is roughly 100 hours, so divide your 10000 by 100 = 100.
> 100 * 4 days is 400 days which is close to your figure. Did they lose a
> couple of 00's in printing the figure which might give you 40000 days. What
> sort of figure would you expect?
>
> I remember at uni having to calculate the MTBF of a system by calculating
> on the MTBF of each component. I couldn't do it now.
>
> Peter
>
> On 10/06/2026 14:42, Ralph Corderoy wrote:
> > Hi,
> >
> > I was idly looking at this power convertor, and saw the ‘MTBF 10000h’.
> > https://www.olimex.com/Products/Power-Supply/Modules/ACDC-85-255-5V0.7A/
> >
> > That's quite a short time for an always-on device.
> >
> >      $ units -1 10000hour time
> >              1 year + 51 day + 10 hr + 11 min + 14.025322 sec
> >
> > Just long enough for a one-year warranty.  :-)
> > Not that MTBF works like that.
> >
> > Skimminghttps://en.wikipedia.org/wiki/Mean_time_between_failures,
> > it is perhaps more of a MTTF value since I don't suppose they get
> > repaired.  And the odds of it lasting a year are about 42%.
> >
> >      R(t) = e^(−λt) = e^(−t / MTBF)
> >
> >      $ bc -l
> >      e(-(24*365)/10000)
> >      .41644536602038009593
> >
> > Where have I gone wrong?
> >
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