Hi,

On Thu, 5 Feb 2004, Jan Kotas wrote:

> If both foo and bar are on the stack the callback will be called
> multiple times for the string: for the argument of foo(), for the
> argument of bar() and finally for the pinned variable in bar(). Only the
> very last one is going to have the pinned bit set.
Oh, now i get it.
But still i couldnt understand how can we keep track of this fact that an
object is no longer pinned.
can you please elaborate on that?

Thanks
archana

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