It should be same as pointer to an array.
void Receive(/*...*/ unsigned char (*SampleData) __gc [])
{
*SampleData = new unsigned char __gc[10];
}
///
unsigned char b __gc[];
Receive(&b);
///
----- Original Message -----
From: "Thomas Tomiczek" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, April 13, 2002 1:53 PM
Subject: [DOTNET] AGAIN: How to define OUT parameter in Managed C++
interface for interop with C#?
I have a function that looks like
void Receive([Out, MarshalAs(UnmanagedType.SafeArray, SafeArraySubType =
VarEnum.VT_UI1)] out byte [] SampleData);
In C# - this is, btw, a line out of a COM interop interface definiition.
I cant use a TLBIMP here - no typelib defined for this, sadly.
Now, I move this C# code (and the interface is only used internally in
the assembly) over to managed C++ (some things this COM object des are
better done in C++), so I need to get this interface defined in managed
C++ (as, again, it is an interface of an external com object.
How to I rewrite this in C++?
void Receive([Out, MarshalAs(UnmanagedType::SafeArray, SafeArraySubType
= VarEnum::VT_UI1)] unsigned char SampleData __gc []);
Is wrong - the SampleData parameter is NOT an OUT parameter, as it
should be.
void Receive([Out, MarshalAs(UnmanagedType::SafeArray, SafeArraySubType
= VarEnum::VT_UI1)] unsigned char *SampleData __gc []);
Throws a compiler error (C2691)
void Receive([Out, MarshalAs(UnmanagedType::SafeArray, SafeArraySubType
= VarEnum::VT_UI1)] unsigned char SampleData __gc []);
Throws a compiler error (C2234)
I have done quite an amount of managed C++ so far, but this is the first
time I need to turn over an array to managed C++.
Can anyone clear me up on the syntax here please?
Regards
Thomas Tomiczek
THONA Consulting Ltd.
(Microsoft MVP C#/.NET)
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