Larry, take the following example...
public long Divide( long x)
{
long i = 0;
try
{
i = x / i;
}
finally;
{
i = 1;
}
return i;
}
The way this code is written you are guarenteed to throw an exeption in the
try block. If I do, what does the caller see? Does the caller see an
exception or does the method return? Based upon my understanding of
try/catch/finally, the return statement never gets executed and the caller
is thrown an exception.
So my point is that a ~really~ smart compiler ~might~ be able to figure that
out and adjust its errors (like the one in the original posting)
accordingly.
The most excellent points made earlier on this thread point out that the
compiler error probably saves our collective buts enough times that we can
just work with it when its not quite as ~smart~ as I would like it. ;-)
Later,
curt
----- Original Message -----
From: "Larry McCoy" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, April 19, 2002 3:05 PM
Subject: Re: [DOTNET] Use of unassigned local variable
Curt,
Why do you say you aren't going to execute the return statement?
As I read the code, the "return author" statement WILL execute after the
finally block completes.
The only way I can see that the return statement wouldn't get executed
is if you had a catch block, and rethrew the exception (but that does
not appear to be what you are doing.) If you do intend to do that, then
you probably would want to put the return statement inside of the Try
block.
HTH
Larry
-----Original Message-----
From: Curtis Koppang [mailto:[EMAIL PROTECTED]]
Sent: Friday, April 19, 2002 8:10 AM
To: [EMAIL PROTECTED]
Subject: Re: [DOTNET] Use of unassigned local variable
I guess it's too much to ask for the compiler to figure this out.
Here is what I mean. If I get an exception on a line in the try block,
the only code I am executing is the code in the finally block. I am not
going to execute the return, so why do I care if it has a valid value or
not.
Later,
curt
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