You are using the namespace-qualified name, correct?
If you have code like this (sorry, don't sprechen sie VB)
namespace Accounts
{
public class AccountForm : Form
{
// ....
}
}
Then this code will create an instance of it:
string sFormName = "Accounts.AccountForm";
Type t = Type.GetType(sFormName);
Form f = (Form) Activator.CreateInstance(t);
Works like a champ for me...
HTH,
Seang
-----Original Message-----
From: Dan Souk [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, April 23, 2002 2:05 PM
To: [EMAIL PROTECTED]
Subject: Re: [DOTNET] AW: [DOTNET] AW: [DOTNET] Load Form by Name
It's your code:)
01 Dim ty As Type =
System.Reflection.Assembly.GetExecutingAssembly.GetType(strFormName)
02 Dim frm As System.Windows.Forms.Form = Activator.CreateInstance(ty)
The exception raised is System.ArgumentNullException, raised on line 02
above. The variable ty is Nothing.
Other notes:
-The form in question (call it frmA) does exist in the GUI project. The
class is public.
-frmA inherits from a base form (call it frmB), also present in the GUI
project.
-Casting obviously isn't the issue at this point because ty is nothing.
-The form is in the GUI layer of the solution, and other projects
(interfaces, data tier, business objects) are also present. Any chance
GetExecutingAssembly is looking in the wrong assembly?
-----Original Message-----
From: dotnet discussion [mailto:[EMAIL PROTECTED]] On Behalf Of
Urs Eichmann
Sent: Tuesday, April 23, 2002 2:40 AM
To: [EMAIL PROTECTED]
Subject: [DOTNET] AW: [DOTNET] AW: [DOTNET] Load Form by Name
> I found the Activator class a little while ago and played around with
> it, but no luck. Seems that the type info is available, but
> Activator.CreateInstance doesn't create an instance of the form.
It DOES create an instance of the form! I use this technique myself for
loading forms dynamically. What does it do in your case? Is there an
exception thrown? Perhaps you should show us the code you use.
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