This is not quite what I want. Launch() will start a NEW instance of the
debugger. What I want to do is:
1.    I start an application in debug mode within the VS.NET IDE (Debug ->
Start)
2.    This application starts a second process (a console app which acts as
a remote server)
3.    I want this his second application to attach itself the *existing*
instance of the debugger, if the debugger is present.
Urs


-----Original Message-----
System.Diagnostics.Debugger.Launch()

-----Original Message-----
From: dotnet discussion [mailto:[EMAIL PROTECTED]] On Behalf Of
Urs Eichmann
Sent: Monday, May 13, 2002 10:57 AM
To: [EMAIL PROTECTED]
Subject: [DOTNET] Automatically attaching a .NET process to a debugger

Does anyone know if it's possible for a .NET EXE to attach itself
automatically to a .NET debugger when it starts (if there is a debugger
present on the machine)?

Thanks for any clues
Urs

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