[DOTNET] Array on struct

[Pierre]

Hi,
I have a structure than contains two arrays with the same value type but
different lenght. Looking on past messages I got some interesting tips. The
C++ structure is:

struct MyStruct
{
 ushort a;
 ushort[4] b;
 ushort[10] c;
}

In C# I translated as:

[StructLayout(LayoutKind.Sequential)]
struct MyStruct
{
 ushort a;
 public ushort_vector_4 b;
 public ushort_vector_10 c;

 [StructLayout(LayoutKind.Explicit)]
 public struct ushort_vector_4
 {
   public const int DataLength = 4;
   [FieldOffset(0)]private ushort Header;
   [FieldOffset((DataLength - 1) * 2)]private ushort Footer;
   public int Length { get { return DataLength; } }
   public unsafe ushort this[int index]
   {
     get
     {
        if ( (index < 0) || (index >= DataLength) )
        {
          throw new IndexOutOfRangeException();
        }
        fixed (ushort *head = &Header)
          return *(head+index);
     }
     set
     {
        if ( (index < 0) || (index >= DataLength) )
        {
          throw new IndexOutOfRangeException();
        }
        fixed (ushort *head = &Header)
          *(head +index) = value;
     }
   }
 }

 [StructLayout(LayoutKind.Explicit)]
 public struct ushort_vector_10
 {
   public const int DataLength = 10;
   [FieldOffset(0)]private ushort Header;
   [FieldOffset((DataLength - 1) * 2)]private ushort Footer;
   public int Length { get { return DataLength; } }
   public unsafe ushort this[int index]
   {
     get
     {
        if ( (index < 0) || (index >= DataLength) )
        {
          throw new IndexOutOfRangeException();
        }
        fixed (ushort *head = &Header)
          return *(head+index);
     }
     set
     {
        if ( (index < 0) || (index >= DataLength) )
        {
          throw new IndexOutOfRangeException();
        }
        fixed (ushort *head = &Header)
          *(head +index) = value;
     }
   }
 }
}

There is an high level of redundancy of the code. Is it possibile to use
only one internal struct defining the size externally ?

Thank you
Pierre

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