Not to me when I tried it... The result was 0. In any case, the result
will be based on the formula applied, which is not what the OP's
question pertains to. My example focused on splitting the initial
number into individual digits in the unconventional way, demonstrated
the use of generic methods as well as the Converter Generic delegate.
I assumed that the -1 in "1701209041-1" was a typo. My code will not
accept anything other than digits in the "number" and will throw an
exception immediately.
On Oct 1, 10:09 am, "Rajendra Prasad Majji" <[EMAIL PROTECTED]>
wrote:
> /* This returned -2 */
>
> using System;
> using System.Collections.Generic;
> using System.Text;
>
> namespace ConsoleApplication1
> {
> class Program
> {
> static void Main(string[] args)
> {
> Calculate("1701209041");
> }
>
> private static void Calculate(string s)
> {
> /*
> if the number its 1701209041-1, the formula will be:
> 1x3 + 7x2 + 0x9 + 1x8 + 2x7 + 0x6 + 9x5 + 0x4 + 4x3 + 1x2 =
> 98. the
> modulo of the divison of 98 by 11 its 10. Then 11 - 10 = 1,
> the Number
> that check if its valid it 1 like the initial number so its
> a valid
> sequence.
> */
> try
> {
> char[] cDigits = s.ToCharArray();
> //int[] digits = Array.ConvertAll<char, int>(cDigits, new
> Converter<char, int>(ConvertCharToInt));
> int[] digits = Array.ConvertAll<char, int>(cDigits,
> Convert.ToInt32);
> double calculo;
> calculo = (digits[0] * 3) + (digits[1] * 2) + (digits[2] *
> 9) + (digits[3] * 8) + (digits[4] * 7) + (digits[5] * 6) + (digits[6] * 5) +
> (digits[7] * 4) + (digits[8] * 3) + (digits[9] * 2);
> calculo %= 11;
> calculo -= 10;
> Console.WriteLine("The value is : " + calculo);
> Console.Read();
> }
> catch (FormatException)
> {
> // Handle the exception.
> }
> }
>
> private int ConvertCharToInt(char c)
> {
> return int.Parse(c.ToString());
> }
> }
>
>
>
> }- Hide quoted text -
>
> - Show quoted text -
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