are you retrieving image or image path from database. ?

kassa
www.elinklanka.com

On Feb 24, 12:42 pm, "m...@ni" <[email protected]> wrote:
> hi Afsal,hru?
>
> wel its better to save the picture name (along with full directory
> path) in the database,when you are insertng the information related to
> picture into the database,
> now what you are doing is, you first save the picture name in the
> database, and you retreive it very well,but when you give a path,it
> doesnt locate the picture,
> .
> Here is a sample code,while inserting picture record into the
> database,i hope it'l solve ur problem.
>
> -----------------------------------------------------------------------------------------------------------------------------------------
> FilePicture.PostedFile.SaveAs(Server.MapPath("CandidateImages\\"  +
> FilePicture.FileName));
>
> this comand will save your picture in that particular folder.
>
> >>>---suppose that "FilePicture" is the id which i gave to the "picture 
> >>>upload control"
> >>>---"CandidateImages" is the folder name, in which m gona save the file 
> >>>into.
>
> -----------------------------------------------------------------------------------------------------------------------------------------
>
> --------------------------------------------------------------------------------------------------------------------
> string PicPath = "CandidateImages\\" + FilePicture.FileName;
>
> now this variable holds the actual path,where that picture is
> placed,you its better to save this variable in the database table i.e
> SqlCommand ObjCom= new SqlCommand("Insert into Table(PicturePath)
> Values(@PicturePath)");
> ObjCom.Parameters.AddParameters("@PicturePath",PicPath);
> --------------------------------------------------------------------------------------------------------------------
>
> -----------------------------------------------------------------------------------------------------------------------------------
> now when u r about to retreive the path in ImageBtn,you just need to
> write like wise:
> ImageButton1.ImageUrl = ds.Tables[0].Rows[0][6].ToString();

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