well, I don't use http server, so there are no http headers :), but thanks
for hints, I think I will use it as I will do new connector for the project
:)

2009/9/7 Andrew Badera <[email protected]>

>
> And now the file is NOT FOUND ... hrmmmmmm ....
>
> Processor ... TcpClient, really? Why so low-level? I do an
> httpwebrequest and stream xml down, loading it into an XmlDoc or XDoc
> or further parsing once I have it (or stream it through an XmlReader
> and parse it line-by-line) ... sure, it's really just a wrapper around
> a socket, but a) I don't see a need to go lower, don't see any value
> or greater accessibility, and b) you get HTTP response codes out of a
> properly conforming system.
>
> ∞ Andy Badera
> ∞ +1 518-641-1280
> ∞ This email is: [ ] bloggable [x] ask first [ ] private
> ∞ Google me: 
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>  OR (andy badera)
>
>
>
> On Mon, Sep 7, 2009 at 4:15 AM, Processor
> Devil<[email protected]> wrote:
> > I think he is trying to achieve this goal using WebBrowser class...
> > WebRequest can do the trick, but the question is "why", is he creating a
> > backdoor controlled with xml?
> > I have this question because now I am working on a very similar project,
> but
> > in my case I use TcpClient to transfer the XML
> >
> > 2009/9/7 Cerebrus <[email protected]>
> >>
> >> Try to programmatically load a simple text file lying on your
> >> filesystem. Does the user *see* your code loading the file ?!?!
> >>
> >> All resources, whether local or remote are just Streams of bytes,
> >> remember. And Streams can be read by StreamReaders.
> >>
> >> On Sep 6, 10:28 am, Niven Sookharan <[email protected]> wrote:
> >> > hi guys
> >> >
> >> > please can someone help me. i'm tryin to extract a line from an xml
> >> > file
> >> > the tricky part is that the source of the file.
> >> >
> >> > the file is the result of a http web request.
> >> >
> >> > eg.www.xmlfile.com/testfile1
> >> >
> >> > how can i extract the a line from the file without the user seeing
> >> > this file or the process.
> >> >
> >> > email me if you have any questions.
> >> >
> >> > thanks, i hope someone out there can help me
> >
>

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