Cannot implicitly convert from string to char is what I get. I had already
tried that before. when I type cast the UInt64 to char it stores its ascii
value rather than number value in string
*char[] _strOutput = new char[10]; // declaration of char array*
*UInt64 _numberToConvert, _nInputNumber;*
*while()*
*{*
* _numberToConvert= _nInputNumber % baseForNumber;
_strOutput[_counter] = (char)_numberToConvert; // this line needs to
store the value which I need to retrieve later on and check
_InputNumber = _nInputNumber / baseForNumber;
_counter++;*
*}*
On Thu, Jul 8, 2010 at 12:50 PM, xzzy <[email protected]> wrote:
>
> while ()
> {
> _strOutput[_counter] = _counter.ToString();
> ++_counter;
> }
>
>
> On Jul 8, 10:38 am, S <[email protected]> wrote:
> > Hello Everyone,
> > I was wondering if anyone has any ideas on how
> > to deal with a situation where I have to store int values in char
> > array. So I want to store '7' in char array but every thing I have
> > tried so far has resulted in no solution.
> >
> > If anyone has better idea I am all ears. I am attaching the following
> > code for everyone's reference.
> >
> > _numberToConvert= _nInputNumber % baseForNumber;
> > _strOutput[_counter] = _numberToConvert; // this line
> > needs to store the value which I need to retrieve later on and check
> > _nInputNumber = _nInputNumber / baseForNumber;
> > _counter++;
> >
> > Anyone any ideas ?
> >
> > - S
