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asp.net
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From:
![]() ![]() rathod_s
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Hi,
this code avoids the postback,but i need to get the values in session on button click and then open the child window.When i come back from child window i get those values from sessions.
So, i will need the postback on button click.
Help please. Anything like session in _javascript_!!!!!!
Thanks.
SwapnilDeshmukh <[EMAIL PROTECTED]> wrote:
asp.net
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| From: SwapnilDeshmukh |
Hi,
The below code might help you to solve your problem
--HTML Code starts here
<%@ Page language="c#" Codebehind="WebForm1.aspx.cs" AutoEventWireup="false"
Inherits="Example.WebForm1" %>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" >
<HTML>
<HEAD>
<title>WebForm1</title>
<meta name="GENERATOR" Content="Microsoft Visual Studio .NET 7.1">
<meta name="CODE_LANGUAGE" Content="C#">
<meta name="vs_defaultClientScript" content="_javascript_">
<meta name="vs_targetSchema"
content="http://schemas.microsoft.com/intellisense/ie5">
<script language="_javascript_">
function Callme()
{
win = window.open("depwin.html", "dep", "height=200,width=400");
return false;
}
function closeDep()
{
if (win && win.open && !win.closed) win.close();
}
</script>
</HEAD>
<body
MS_POSITIONING="GridLayout" >
<form id="Form1" method="post" runat="server">
<asp:Button id="Button1" runat="server"
Text="Button"></asp:Button>
</form>
</body>
</HTML>
--C# Code starts here
using System;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Web;
using System.Web.SessionState;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.HtmlControls;
namespace Example
{
/// <summary>
/// Summary description for WebForm1.
/// </summary>
public class WebForm1 : System.Web.UI.Page
{
protected System.Web.UI.WebControls.Button Button1;
private void Page_Load(object sender, System.EventArgs e)
{
Button1.Attributes.Add("onclick","return Callme();");
}
#region Web Form Designer generated code
override protected void
OnInit(EventArgs e)
{
//
// CODEGEN: This call is required by the ASP.NET Web Form Designer.
//
InitializeComponent();
base.OnInit(e);
}
/// <summary>
/// Required method for Designer support - do not modify
/// the contents of this method with the code editor.
/// </summary>
private void InitializeComponent()
{
this.Load += new System.EventHandler(this.Page_Load);
}
#endregion
}
}
Hope this helps u
Regards
Swapnil Deshmukh
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