On Wed, Oct 17, 2018 at 08:17:20PM +0530, Nishad Kamdar wrote:
+       chip->rdwr_pin = devm_gpiod_get(&spi_dev->dev, "rdwr", GPIOD_IN);
+       if (IS_ERR(chip->rdwr_pin)) {
+               ret = PTR_ERR(chip->rdwr_pin);
+               dev_err(&spi_dev->dev, "Failed to request rdwr GPIO: %d\n",
+                       ret);
                return ret;
        }
-       gpio_direction_input(chip->rdwr_pin);
-       ret = devm_gpio_request(&spi_dev->dev, chip->convert_pin,
-                               spi_get_device_id(spi_dev)->name);
-       if (ret) {
-               dev_err(&spi_dev->dev, "Fail to request convert gpio PIN %d.\n",
-                       chip->convert_pin);
+       chip->convert_pin = devm_gpiod_get(&spi_dev->dev, "convert", GPIOD_IN);
+       if (IS_ERR(chip->convert_pin)) {
+               ret = PTR_ERR(chip->convert_pin);
+               dev_err(&spi_dev->dev, "Failed to request convert GPIO: %d\n",
+                       ret);
                return ret;
        }
-       gpio_direction_input(chip->convert_pin);
-       ret = devm_gpio_request(&spi_dev->dev, chip->busy_pin,
-                               spi_get_device_id(spi_dev)->name);
-       if (ret) {
-               dev_err(&spi_dev->dev, "Fail to request busy gpio PIN %d.\n",
-                       chip->busy_pin);
+       chip->busy_pin = devm_gpiod_get(&spi_dev->dev, "busy", GPIOD_IN);
+       if (IS_ERR(chip->busy_pin)) {
+               ret = PTR_ERR(chip->busy_pin);
+               dev_err(&spi_dev->dev, "Failed to request busy GPIO: %d\n",
+                       ret);
                return ret;
        }

Hm, from what I can tell devm_gpio_request() is allocating some memory,
which makes this a series of 4 allocations.

What happens if the fourth allocation fails? Do we leak the first three?

--
Thanks,
Sasha
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