Hallo Stefanie,

you may query the database.
Here is a query which will give you all the bitstreams of the items
which are in_archive are not of internal format. Derived bitstreams like
extracted text, thumbnail and licenses are excluded:
select bf.mimetype, count (b.bitstream_format_id) as Anzahl,
bf.bitstream_format_id from bitstreamformatregistry bf , bitstream b
where b.bitstream_format_id=bf.bitstream_format_id and bf.internal=false
and b.bitstream_id in (select bitstream_id from bundle2bitstream where
bundle2bitstream.bundle_id in (select resource_id from metadatavalue
where text_value='ORIGINAL' and metadata_field_id=64 and
resource_type_id=1 and resource_id in (select bundle_id from item2bundle
where item_id in (select item_id from item where in_archive=true and
owning_collection in (select collection_id from community2collection
where community_id=YOUR_COMMUNITY_ID))))) group by bf.mimetype,
bf.bitstream_format_id order by bf.mimetype;

Replace the YOUR_COMMUNITY_ID with the real one.

You'll get something like:
           mimetype            | anzahl | bitstream_format_id
-------------------------------+--------+---------------------
 application/pdf               |     50 |                   3
 application/postscript        |      2 |                  24
 application/vnd.ms-powerpoint |      4 |                   8
 video/quicktime               |      1 |                  25
(4 rows)



Hoffe das hilft

Claudia Jürgen




Am 11.04.2017 um 10:14 schrieb Stefanie Behnke:
Dear all,



what is the easiest way to get the number of all bitstreams in a community? The 
number of items in one community is 4460, and I now want to know how many 
bitstreams are there, if possible, ordered by mimetype.



Thanking you in advance

Stefanie


--
Claudia Juergen
Eldorado

Technische Universität Dortmund
Universitätsbibliothek
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