Hey Robert,
> If I have foo(), where
>
> foo() {
> return(bar());
> }
>
> then should I expect anything unusual about args[1]
> in fbt::foo:return? Should I expect args[1] in such
> a probe to give me X where
>
> X = foo()
If the code above were compiled into a tail call, the foo:return probe would
fire before the bar:entry probe. The value of arg1 or args[1] will not contain
the value returned to the caller of foo().
To trace that value, one can write a simple script:
foo:entry
{
self->follow = 1;
}
bar:return
/self->follow/
{
trace(arg1);
self->follow = 0;
}
This applies both for user-land and the kernel.
Adam
--
Adam Leventhal, Fishworks http://blogs.sun.com/ahl
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