Dear Thomas,
Thank you for your response and your hint. I am clear now!
Have a nice day.
Mai
On 30.11.2016 08:23, Thomas Fetzer wrote:
Hi Mai,
it depends, when you print this->timeManager().time(). In your case,
you have to add this->timeManager().timeStepSize(). Although your
Newton has already converged the time is updated after
problem_->writeOutput() is called, see timemanager.hh.
Kind regards,
Thomas
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Dipl. Ing. Thomas Fetzer
Institut für Wasser- und Umweltsystemmodellierung (IWS)
Lehrstuhl für Hydromechanik und Hydrosystemmodellierung
Universität Stuttgart, Pfaffenwaldring 61, 70569 Stuttgart
Email: [email protected]
Telefon: 0049-711-685-60103 ** fax: 0049-711-685-60430
http://www.hydrosys.uni-stuttgart.de
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Am 11/29/2016 um 03:29 PM schrieb Trung Hieu Mai:
Dear Dumux,
Recently, I discovered the value of this->timeManager().time() in void
addOutputVtkFields() always 1 time step before as in VTK output. Is it a
bug in Dumux?
More detail: During comparing a time dependent analytical solution with
a Dumux simulation, I have added an anaSol variable in
addOutputVtkFields(). The variable anaSol is calculated as a function of
time which called by this->timeManager().time(). In the results, I
found some lagging between anaSol and simulation result. Printing out
the value from this->timeManager().time(), I found that the time is
always 1 time step before as in VTK (Ex: with time step 810s, the time
in VTK results are 0, 810, 1620...and the this->timeManager().time()
returns value: 0, 0, 810 respectively)
Best wishes,
Mai
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