Re: [Dynapi-Dev] Thread.prototype = new DynObject

[Jordi - IlMaestro - Ministral]

By making thread a dynobject, it gets a unique identifier that is usable
anytime. You also get all the methods of a DynObject, but don't worry about
overweight. You only bind the prototype chains of both objects, making all thos
DynObject method available to the Thread, but they are not copied and no extra
memory is needed.

[EMAIL PROTECTED] wrote:

> question I got lost from this one :
>
> function Thread(dlyr) {
>         // Inherit from object. Provides unique ID
>         this.DynObject = DynObject
>         this.DynObject()
>
>         this.setDynLayer(dlyr);
> }
> Thread.prototype = new DynObject;
>
> now let's say that on a page I have :
>
> thread = new Thread();
>         thread.sleep(20);
>         thread.run = function() {
>                 status = "run";
>                 hover.run();
>                 circle.run();
>                 path.run();
>         }
>         thread.start();
>
>         alert(thread.deleteFromParent)
>
> this will alert function(){bla bla bla }
>
> and I cna do the same for each method of DynObject
>
> now my question is why attaching all those method to something like thread?
>
> it will never use 'em or am I missing something?
>
> ciao
> Y
>
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