Sorry for my last messy post. Here is a much better version:
I tried the following code, but the layer 'myLayer' didn't get hidden. Any
idea
what I do to make it hidden?
<div id='mylayer'></div>
<script>
d = new DynLayer();
d.setID('mylayer');
d.assignElement(is.ie?document.all.mylayer:document.layers.mylayer);
d.setVisible(false) //This doesn't work
</script>
----Original Message Follows----
From: Dan Steinman <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED]
Subject: Re: [Dynapi-Dev] Question about DynAPIObject
Date: Sat, 10 Nov 2001 00:37:26 -0500
The reason for DynAPI to create the layer/div is to make it easier. There's
nothing stopping you from creating your layers manually, and then attaching
them to a DynLayer afterwords like so:
<div id='mylayer'></div>
<script>
d = new DynLayer();
d.setID('mylayer');
d.assignElement(is.ie?document.all.mylayer:document.layers.mylayer); //
assignElement is re-introduced in 2.6
</script>
In the current paradigm, creation works similarly to Java does. You create
a GUI object, and add that to some other object. Dynlayer needs to know
what object to be created in, be it another layer, or the document. It
wouldn't be a good idea for the constructor to create the browser element
(during "new DynLayer()") because it would have to be created again when you
add it to another layer (nesting). And things have been optimized so that
the layer is only created when all it's size/location/color has been
finalized so to reduce unneeded processing.
Regards,
Dan Steinman
On Fri, Nov 09, 2001 at 11:32:31PM +0000, Quang Nguyen wrote:
> I guess we create a DynAPI object to make sure the Dynapi.js and any
library
> needed have been loaded.
> However, what are the technical reason why we need DynAPI to create a
layer,
> like the following:
>
>
> ...
> DynAPI.onLoad = function()
> {
> myLayer = new DynLayer()
> myLayer.setSize(100,100)
> myLayer.setBgColor('#c0c0c0')
> myLayer.moveTo(100,100)
> DynAPI.document.addChild(myLayer)
> }
> ...
>
>
>
> In short, why does the layer myLayer not appear if you write like this:
>
> ...
> myLayer = new DynLayer()
> myLayer.setSize(100,100)
> myLayer.setBgColor('#c0c0c0')
> myLayer.moveTo(100,100)
> ...
>
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