function foo(x,y,z) { this.DynLayer = DynLayer; this.DynLayer(); } foo.prototype = new DynLayer()
I've seen this type of thing in a couple examples (as part of the object definition). 1) what does it mean to do a foo.prototype? I understand when you do something like foo.prototype.isCool=true or foo.prototype.setColor=function(col) but not the one that isn't 'adding' some object/function to the object prototype. 2) the first 2 lines.... I'm guessing that you instantiated the object by saying new foo(x,y,z)...this somehow created made the object a DynLayer because of the foo.prototype...Then since it's a DynLayer you're pointing the this.DynLayer property to the DynLayer function and then initializing it with the this.DynLayer() function call??? That doesn't make much sense...so any clarification would be great, thanks! -James _________________________________________________________________ Join the world’s largest e-mail service with MSN Hotmail. http://www.hotmail.com ------------------------------------------------------- This sf.net email is sponsored by: OSDN - Tired of that same old cell phone? Get a new here for FREE! https://www.inphonic.com/r.asp?r=sourceforge1&refcode1=vs3390 _______________________________________________ Dynapi-Help mailing list [EMAIL PROTECTED] https://lists.sourceforge.net/lists/listinfo/dynapi-help