Dear James Conklin, Adding more math to the debate.
Regarding your second point: > 2. The ocean is a spherical body of water. The ocean volume varies as > the cube of the ocean radius. Therefore, for the ocean radius to increase > 20 feet, the ocean volume must increase 8,000 times more than for a 1-foot > radius increase. For the ocean radius to increase 40 feet, the ocean > volume must increase 64,000 times more than for a 1-foot radius increase. > For the volume of a sphere to increase by 1 foot (let's simplify the math and say 0.5 m), in which the sphere has a radius of 6400km, would require changing the volume of 4/3 pi r^3 by increasing r by 0.5. Then, to compare that with a 10m increase (20 x the 0.5). Volume "as is" = 1.0979 x 10^^21 (if the world were water) 0.5 m increase = 1.0979 x 10^^21 ^ within rounding error. 10 m increase = 1.0979 x 10^^21 within rounding error. This basically suggests that the increase of 1 foot would be a very very small percentage of the total. So, your scale of 6,400 times is still a small volume of liquid relative to the frozen ice and temperature expansion available. I find it interesting that there are so many ways to calculate that 64000 times something very small is still small! I also wonder what exactly is the inconvenient part of all this? Jim. -- ------------------------------------- James J. Roper, Ph.D. Universidade Federal do Paraná Depto. de Zoologia Caixa Postal 19020 81531-990 Curitiba, Paraná, Brasil ===================================== E-mail: [EMAIL PROTECTED] Phone/Fone/Teléfono: 55 41 33611764 celular: 55 41 99870543 ===================================== Zoologia na UFPR http://zoo.bio.ufpr.br/zoologia/ Ecologia e Conservação na UFPR http://www.bio.ufpr.br/ecologia/ ------------------------------------- http://jjroper.googlepages.com/home Currículo Lattes http://lattes.cnpq.br/2553295738925812
