> Hi ,
>
> We are using the example program in the following way.
>
>
> double x = 3.0, result;
> result = sqrt(x);
> diag_printf("\nThe square root of x=%lf is result=%lf\n",
> x,result);
>
>
> The Result is in the following way with out any values.
>
> The square root of x=%f is result=%f
>
> Thank you,
> S.Ramesh Chandra.
>
In the link posted previously, there was discussion that mentioned that
diag_printf doesn't have floating support. The %f's just pass right
through.
You'll need to switch to plain printf, and verify that it has the
floating point option enabled, or do some additional conversion to turn
your floats into strings, and send them out using %s.
Byron Jacquot
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