Serve me right for not checking my work. Here's a correction:
On Wed, 31 Jan 2001 12:37:13 GMT, [EMAIL PROTECTED] (Duncan Murdoch)
wrote:
>To find it, do this. Suppose the quadratic curve is A x^2 + B x + C.
>Then you've got three equations:
>
> A (-1)^2 + B (-1) + C = 2.05
> A (0)^2 + B (0) + C = 6.38
> A (1)^2 + B (1) + C = 12.08
>
There's a unique solution to these equations; it is C = 6.38, A =
(12.08+2.05)/2-C, B = (12.08-2.05)/2-C. Those are the least-squares
parameter estimates.
Duncan Murdoch
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