On Thu, 29 Nov 2001 14:37:14 -0400, Gus Gassmann
<[EMAIL PROTECTED]> wrote:

> Rich Ulrich wrote:
> 
> > On Thu, 29 Nov 2001 15:48:48 +0300, Ludovic Duponchel
> > <[EMAIL PROTECTED]> wrote:
> >
> > > If x values have a normal distribution, is there a normal distribution
> > > for x^2 ?
> >
> > If z is standard normal [ that is, mean 0, variance 1.0 ]
> > then z^2  is chi squared with 1 degree of freedom.
> >
> > And the sum of S   independent  z  variates
> > is chi squared with S degrees of freedom.
> 
> Hold it! The sum of S independent z variates is normal.
> The sum of the _squares_ of S independent z variates is
> chi squared with S degrees of freedom.
> 
> (But I am sure you knew that.)

oops- make that < z^2 >  for < z >  of course -


-- 
Rich Ulrich, [EMAIL PROTECTED]
http://www.pitt.edu/~wpilib/index.html


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