In a stochastic process the number of customers which are arriving at a
server (during a time intervall) is desribed by a Poisson distribution:
P(n)=exp(-v) * (v^n)/(n!)
Each arriving customer has a task to be carried out of which the size (in
units) is described by a lognormal distribution:
f(u)= exp(-(ln u)^2 / (2*a^2)) / (u*a*SQRT(2*PI))
Question: What is the total number of units (i.e. size of all tasks)
requested during the time intervall ?
I wonder how these distributions can be concatenated, and if there is a
formula for this.
Thanks for any help!
Jacek Gomoluch
=================================================================
Instructions for joining and leaving this list and remarks about
the problem of INAPPROPRIATE MESSAGES are available at
http://jse.stat.ncsu.edu/
=================================================================
