Can you help me solve this problem:
There are 8 baskets and 4 apples. Thrown at random, 3 of the 4 apples
can go to any basket. The 4th apple, however, can only be thrown into
baskets 1 through 4. What is the probability that there is no more than
one apple in every basket?
Now, I can easily solve this problem if the 4th apple could also go to
any of the 8 baskets. The probability referred to above can be computed
as follows:
P = factorial(8)/((8 to the power of 4)*factorial(8-4)) = 0.41015625.
But the restriction for the 4th apple to only be limited to baskets 1
thru 4 would obviously change that probability. How?
Thanks
ZA
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