Hi!

I am working on a linear regression model where both my x and y values
contain errors. In fact, they are repeated measurements of the same
samples -- I am doing this to see if the measuring device is working
properly. I found least square fitting formulas at

http://mathworld.wolfram.com/LeastSquaresFitting.html

and also I found maximum likihood estimate formulas for variables both
containing errors on a book by Forman S.Acton -- Analysis of Straight
Line Data. I am getting approximately correct results, but I am
wondering if there is a way to find out what the variance and standard
deviation of the regression parameters are. For example, if in my
y=mx+b equation, m is found to be .9678, could I somehow find the
confidence interval for the slope?

I have the book Mathematical Statistics: Basic Ideas and Selected
Topics by Peter Bickel at hand but the reading is giving me a lot of
headaches.... I greatly appreciate your help : )

Thanks!


Shirley.


Hi!

I am not sure if my previous message is clear enough... here is part
of my data:

834.0 804.0
1061.0 1019.0
466.0 446.0
531.0 514.0
1037.0 1006.0
634.0 614.0
390.0 377.0
504.0 508.0
546.0 516.0
569.0 547.0
655.0 630.0
704.0 665.0
714.0 698.0
1181.0 1128.0
712.0 673.0
488.0 476.0
462.0 439.0
490.0 470.0
...... 

and here is my result:

Using perpendicular offsets:
m       = 1.0000218762548265
b       = -21.93534402271200
Residuals:
sum     = 10598.829125279093
sumSqrt = 144880.87203048688
----------------------------
Using maximum liklihood
m       = 0.9695748177645382
b       = 0.2864222371090363
Residuals:
sum     = 7557.882289767819
sumSqrt = 97142.18567110984

I am not sure why they gave me different results either (because the
perpendicular offset is supposed to minimize the sum of squares of the
residuals but the second set of m and b is actually giving me smalled
residual sums. If I assume the x and y variables have equal error,
which is normally distributed with the expected value of 0, is there
anyway of finding out the variance of the regression parameters, or
the slope and the intercept?

a milliam thanks :^)


Shirley


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