On 3 Apr 2002 08:36:47 -0800, [EMAIL PROTECTED] (david) wrote: >u=2.7 minutes >sigma=.6 minutes > >my main question is how do I get the Z value here? > >The question is something like this what is probability that the total >check out time for next customers is less than 90 minutes? > >- I understand that Xi is (i=1,2,3) and > W = X1 + X2 . . . . and > P(W<90) = P(X bar<3) > >BUT > >How does (X bar<3) = P(Z<2.74) > >So my main question is how does (X bar<3)=P(Z<2.74)? > >Could someone please explain how does this work? > >Thanks in advance!
check out this site: http://psych-www.colorado.edu/~mcclella/java/normal/normz.html It should give you a hint on how to obtain Z scores from a normal distribution of scores. Are you sure about the above data? A mu of 2.7 and a standard deviation of .6 with a -90 score seems a tad off kilter to me. Maybe, I'm missing something here. . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
