On 11 Jul 2002, Jussi Piitulainen wrote in part:

> What I worked out is, various "means" can be taken to be functions
> from something like vectors (of varying lengths) to real numbers as
> follows. This is indeed elegant.
>
>     A (x1,...,xn) = sum_k (1/n) xk      (arithmetic mean)
>     G = exp o A o log                   (geometric mean)
>     H = reciprocal o A o reciprocal     (harmonic mean)
>     R = squareroot o A o square         (root-mean-square)
>
> And in general, I would now take `conjugate of X under transform f' to
> mean f^-1 o X o f where f is applied to elements of vector, X takes a
> vector to a scalar, and f^-1 "undoes" f.
>
> Is this all right? Is there a better way to understand this concept?
> What else might I find in place of X and f?

You appear to have understood the basic concept, although I think your way
of expressing it may be somewhat misleading.  For what it may be worth,
I would describe the situations thus:

Given a set of numbers X_k (k=1,...n), one calculates a mean by
 (1) applying a transformation T to each of the numbers;
 (2) summing all the transformed numbers;
 (3) dividing that sum by n;
 (4) applying the inverse transformation T' to the quotient of (3).

In the case of the arithmetic mean, T = T' = the identity transform;
 for the geometric mean, T = the logarithm (to any convenient base b)
and T' = the antilogarithm (to the same base),
so that if T = ln, T' = exp;
 for the harmonic mean, T = T' = the reciprocal;
 for the RMS (root mean square), T = square and T' = square root.

This schema has the advantage that the arithmetic mean is more clearly
seen to behave just like the others, with a suitable choice of
transformation (namely, the identity).

In language similar to the notation you used above, we might write

   mean = T'(sum_k (1/n) Txk)

and the particular mean one gets depends on one's choice of T.

Cheers!        -- Don.
 -----------------------------------------------------------------------
 Donald F. Burrill                                            [EMAIL PROTECTED]
 184 Nashua Road, Bedford, NH 03110                       (603) 471-7128

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