You've understood me perfectly.  I want the interaction and there will
be 6 values graphed.  Now I understand why the multiplication by 2
(which is unnecessary).

To restate what you said, if I want an error bar (1 SE) for the
interaction it's simply:

Sqrt(MSEinteraction/18)

Correct?
There will be six bars and each bar represents 18 subjects.

Allyson

-----Original Message-----
From: Donald Burrill [mailto:dfb@;mv.mv.com] 
Sent: Friday, October 25, 2002 3:56 PM
To: Allyson
Cc: [EMAIL PROTECTED]
Subject: Re: error bars on histogram for ANOVA interaction

Allyson, there are a couple of points that may need to be clarified:
especially if I have incorrectly interpreted what you meant (and I'll
try
to be clear about what I've inferred between the lines).

On 25 Oct 2002, Allyson wrote:

> I'm trying to plot error bars from the results of an ANOVA (Group[2x18
> people in each group], Effect[3 levels repeated measure]).  I'd like
> to use the MSError to do this.  Please tell me if I'm correct

First clarification needed:  whether the means you want to plot (or so
one
presumes -- those are what error bars are commonly attached to) are the
means of the Group main effect, of the "Effect" main effect, or of the
Group-X-Effect interaction.  Your "Subject:" line mentions
"interaction",
so I'll assume that's what you meant:  that is, that you want to display
a graph of six different means (whose values are plotted on the ordinate
of the graph):  a thing that might look something like this:

    +
    -         G1
    -                   G1
    -
    -
    +                   G2
    -                             G1
    -
    -
    -         G2
    +                             G2
    -
      --------+---------+---------+----
              E1        E2        E3

 with (vertical) error bars on the plotted points (that I've labelled G1
and G2, for the pertinent Group);  and you might want to connect the
three
"G1" points with straight lines, and similarly for G2, which is not
something I can do in this medium.

> to generate an error bar from the MSError from an effect:
> sqrt((MSE*2)/n)

You haven't said what kind of error bar you have in mind.  Sometimes one
wants (mean +/- 1 standard error of the mean), which would not entail
your
multiplication by 2;  sometimes one wants to represent a 95% (or in
general a [1-alpha] confidence interval, which would entail multiplying
the standard error by, approximately, 2 -- but after one had taken the
square root, not before.  It is not clear to me why MSE would be
doubled.

The value for "n" is the number of cases represented by each mean to be
displayed:  for the G effect that would be 18*3 = 54;  for the E effect
it
would be 18*2 = 36;  for the GE (interaction) effect it would be 18.
(Hence your "36*3" in the next line is incorrect, regardless of whether
you meant it to be enclosed in parentheses (so as to divide (2*MSE) by
108) of not (so as to divide (2*MSE) by 12, effectively).)

> errorBarValueOfInteraction=sqrt((MSEOfIntraction*2)/36*3)
>
> Then each bar value in the histogram of component scores would have
> the same sized error bar?

Yes.  You would be using the pooled variance estimate for the E and EG
effects.  (Note:  the MSE for G is not the same as the MSE for E and EG
in
this repeated-measures design.  The former is likely to be an order of
magnitude larger than the latter, at least in the usual situation where
Ss that score high on one of the repeated measures tend also to score
high on the others.)

> Forgive me if I'm clueless.

We all were, once;  and still are, some of the time, about some things
at
least.

I hope this has been helpful.  If I've incorrectly understood what you
intended, please let me know;  if you don't understand something I've
written, ask for clarification.  (I'm not TRYing to be obscure!)
                  -- DFB.
 -----------------------------------------------------------------------
 Donald F. Burrill                                            [EMAIL PROTECTED]
 56 Sebbins Pond Drive, Bedford, NH 03110                 (603) 626-0816
 [was:  184 Nashua Road, Bedford, NH 03110               (603) 471-7128]

.
.
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