Forgive me if this is a repost I'm trying to generate error bars for a histogram of an ANOVA. I would like to use the MSError for the effect.
Here's the ANOVA design: 1.2 Between groups (18 subjects in each) 2.3 repeated measures I have been told that to derive the error bars for the effect one does the following: errorbarsize=sqrt((MSE*2)/n) Would I be correct in doing the following: sqrt((MSErrorInteraction*2)/(36*3)) Then the error bar would be the same size for all the values. That doesn't sound right. Am I clueless? If so, please set me straight. thanks, Allyson . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
