John <[EMAIL PROTECTED]> writes:
> Please let me know if there a formula for the expansion of
> (X1+1)(X2+2)(X3+3)...(Xn+n).
That depends on what you mean by a formula.
If you do a variable substitution: Xk -> k*Yk, your product becomes
n!(Y1+1)(Y2+1)(Y3+1)...(Yn+1)
You can expand this as:
n! (1 + Sum(Yk) + Sum (Yj*Yk) + Sum (Yj*Yk*Yl) + ... )
j<>k j<>k<>l
Does this help?
Scott
--
Scott Hemphill [EMAIL PROTECTED]
"This isn't flying. This is falling, with style." -- Buzz Lightyear
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