You are right, it is not symmetric, absolutely.  The difference is small,
except near the extremes, and I believe for low n.

My ref. is a 1963 text and the equations are not simple.  And they are still
approximations.  Later I can provide them, but not this moment.  :(

If you want the full & compelte thing, you will have to work through using a
binomial distribution and eqs. for same.

Jay

sleszyk wrote:

> U�ytkownik "Fred Ettish" <[EMAIL PROTECTED]> napisa3 w wiadomo�ci
> news:[EMAIL PROTECTED]
> > A recent poll by the Pew Group of 15000 Muslims world wide found 71%
> support
> > Bin Laden. Looking at my textbook the formula for a population proportion
> > is:
> >
> > p +/- Z * SQRT ( p(1-p)/n )
> >
> > Ok simple enough, but my question is doesn't the population size affect
> the
> > confidence interval? How does the fact that their are 2000000000 affect
> the
> > interval?
> >
> > Thanks
> >
> >
>
> I have another question about the proportion confidence interval:
>
> With the above formula one can calcute the symmetrical interval, which is ok
> as long as the proportion is not too close to 0 or 1.
> However, from what I've heard the "real" CI is always asymmetrical (well,
> maybe except for p=0,5).
>
> Does anybody know how to calculate an asymmetrical CI for a proportion?
> I've been looking for an answer on the web some time ago and couldn't find
> it.
>
> Thanks,
> Peter.
>
> --
> Serwis Usenet w portalu Gazeta.pl -> http://www.gazeta.pl/usenet/
> .
> .
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--
Jay Warner
Principal Scientist
Warner Consulting, Inc.
4444 North Green Bay Road
Racine, WI 53404-1216
USA

Ph: (262) 634-9100
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