I know that Pochhammer symbol is (x)_n and it is equal to x*(x+1)*(x+2)...(x+n-1). When all x's are different, I have x_0*(x_1+1)*(x_2+2)...(x_n+n) for (n+1) factors or x_0*(x_1+1)*(x_2+2)...(x_(n-1)+(n-1)) for n factors. If you know the expansion of x_0*(x_1+1)*(x_2+2)...(x_n+n), please let me know.
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