In tossing four fair dice, what is the probability of tossing at most one 3?
Answer : 0.868 My solution and answer: Let A = total number of sample points B = sample points with at most one 3 Pr(B/A) = 5*6*6*6 / 6*6*6*6 = 1080 / 1296 = 0.8333 Where is my error? . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
