Hi! My class had this exercise to do but no one seams to know how to do it... So we need a hand! :)
The exercise is the following: A coin was launched 320 times. Grouped in 80 sequences of 4 launches each in the same order they were "conceived". The following happened Quantity os heads 0 1 2 3 4 Quantity of Sequences 6 22 35 11 6 Meaning: 6 sequences with no heads, 22 sequences with 1 head, 35 seq. with 2 heads... etc Now: If the coin is balanced so the quantity of heads in each seq. of 4 lauches is a aleatory binomial variable with parameters n=4 e p=50%. Test this hipotesis using the Chi-Square method with 5% significance Test now, with 5% significance, now using the total proportion of heads Those we were able to do.. now the hard question: Did you get to the same conclusion on the 2 situations? This will happen to any sample and the tests are equivalent?? WHY???????? HELP PLEASE!!!! NEED ANSWER....... THANKS!!!!!!!!!! . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
