Bin,

I report from Watson et al. (1990 - p. 403)(1) following your notation:

Ho: mE = mC
Ha: mE <> mC

t=(mE - XmC)/SQRT[(s2E/nE)+(s2C/nC)]

The confidence interval is defined as [-t(alpha/2),v;+t(alpha/2),v]
where v=A/B, and 

A=[(s2E/nE)+(s2C/nC)]2
B=[(s2E/nE)2/(nE-1)]+[(s2C/nC)2/(nC-1)]

HTH,
Luca

Mr. Luca MEYER
Consumer research advisor
http://lucameyer.com/

(1) Watson, C.J, Billingsley, P., Croft, D.J. & Huntsberger, D.V. (1990)
"Statistics for Management and Economics" 4th ed. Allyn and Bacon

> -----Messaggio originale-----
> Da: [EMAIL PROTECTED] 
> [mailto:[EMAIL PROTECTED] Per conto di Bin
> Inviato: luned� 13 ottobre 2003 6.09
> A: [EMAIL PROTECTED]
> Oggetto: [edstat] help for t-Test of Difference of Means with 
> different sapmle sizes
> 
> 
> I found the following formula
> ************
> Let E be the experimental condition and let C be the control 
> condition. Let m be the means, s the standard deviations, and 
> n be the sample size. Then t = (mE - mC) / SQRT[(s2E + s2C) / n ] 
> for the case of equal sample sizes, n, in both groups. See Levin
> (1999: 25) for the formula when sample sizes differ.
> ************
> in my case, the sample sizes is different, But I can not find 
> the formula. Could you please tell me the formula for t-Test 
> of Difference of Means with different sapmle sizes?
> 
> Thanks.
> .
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