Hi,
I'm facing the following issue: Assuming a set of measurements: (m(i); sd(i)) with u(i) = measured value and u(i) = standard uncertainty If one could propose the overall mean value mtot as being the weighted mean value: mtot = sum(w.*m/sum(w)) with w(i)=1/u(i)^2, what the hell could be the overall variance vartot: 1) the weigthed variance of the mean values m(i) 2) the weighted mean value of the variances u(i)^2 This problem looks like an ANOVA but it's not. Could anyone help me ? Thanks Chris . . ================================================================= Instructions for joining and leaving this list, remarks about the problem of INAPPROPRIATE MESSAGES, and archives are available at: . http://jse.stat.ncsu.edu/ . =================================================================
